Python Practice : To Sort a Dictionary by its Values Using String and Random Modules

Random module in Python is very interest to play with, let's see what we can do with this little project.

What to achieve: 

To use Random methods to create 10 random words with random number of length of alphabets, such as (ced,sghe,d,ewgt....)

Then create a dictionary with 0 through 9 in random order as keys, and the 10 random words as values.

The outcome is to print out a sorted dictionary by values. 

Let's see the code below:

import string
import random

keys= list(range(0, 10))
random.shuffle(keys)  
print(f'1  {keys}')
values = string.ascii_lowercase

dict_first= {}
for key in keys:
    word = "".join(random.sample(values,random.randint(1, 5)))
    dict_first[key] = word
print(f'2  {dict_first}')
print(f'3  {sorted(dict_first)}')
print(f'4  {sorted(dict_first.items())}')

dict_second={}
for k,v in dict_first.items():
    dict_second[v] = k

print(f'5  {sorted(dict_second)}')
print(f'6  {sorted(dict_second.items())}')

The output is like this:

1 [1, 5, 9, 3, 2, 0, 4, 7, 8, 6]
2 {1: 'xvh', 5: 'onwaj', 9: 'mfq', 3: 'qkwsx', 2: 'gqrc', 0: 'f', 4: 'xhkgc', 7: 'd', 8: 'egh', 6: 'tvm'}
3 [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
4 [(0, 'f'), (1, 'xvh'), (2, 'gqrc'), (3, 'qkwsx'), (4, 'xhkgc'), (5, 'onwaj'), (6, 'tvm'), (7, 'd'), (8, 'egh'), (9, 'mfq')]
5 ['d', 'egh', 'f', 'gqrc', 'mfq', 'onwaj', 'qkwsx', 'tvm', 'xhkgc', 'xvh']
6 [('d', 7), ('egh', 8), ('f', 0), ('gqrc', 2), ('mfq', 9), ('onwaj', 5), ('qkwsx', 3), ('tvm', 6), ('xhkgc', 4), ('xvh', 1)]